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Maths MCQ Class 11 Ch-10 | Straight Lines
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Mathematics
MCQ | Class 11 | Chapter 10
STRAIGHT LINES
Multiple Choice Questions (MCQ)
- MCQ Based on the Angle of inclination.
- MCQ Based on the Slopes of the straight lines
- MCQ Based on the Different Types of Straight Lines.
Features
- In this pdf given below you find the important MCQ which are strictly according to the CBSE syllabus and are very useful for the CBSE Examinations.
- Solution Hints are also given to some difficult problems.
- Each MCQ contains four options from which one option is correct.
- On the right hand side column of the pdf Answer option is given.
Action Plan
- First of all students should Learn and write all basic points and Formulas related to the Continuity and Differentiability.
- Start solving the NCERT Problems with examples.
- Solve the important assignments on the Straight Lines Chapter 10 Class XI.
- Then start solving the following MCQ.
MCQ | CHAPTER 10 | CLASS 11
STRAIGHT LINES
Question 1What is the distance between (1, 3) and (5, 6)?
a) 3 units
b) 4 units
c) 5 units
d) 25 units
Answer: c
Question 2
What is the distance of (5, 12) from origin?a) 6 units
b) 8 units
c) 10 units
d) 13 units
Answer: d
Question 3
The locus of a point, whose abscissa and ordinate are always equal is
(a) x + y + 1 = 0
(b) x – y = 0
(c) x + y = 1
(d) none of these.
Answer: b
(a) x + y + 1 = 0
(b) x – y = 0
(c) x + y = 1
(d) none of these.
Answer: b
Solution Hint: Let the
coordinate of the variable point P is (x, y)
Now, the abscissa of this point = x
and its ordinate = y
Given, abscissa = ordinate
⇒ x = y
⇒ x – y = 0
So, the locus of the point is x – y = 0
Now, the abscissa of this point = x
and its ordinate = y
Given, abscissa = ordinate
⇒ x = y
⇒ x – y = 0
So, the locus of the point is x – y = 0
Question 4
Angle made by line with ____________ measured anticlockwise is called inclination of the line.
a) positive x-axis
b) negative x-axis
c) positive y-axis
d) negative y-axis
Answer: a
Question 5
Slope of a line is given by _________ if inclination of line is α.
a) sinα
b) cosα
c) tanα
d) cotα
Answer: c
Question 6
The equation of straight line passing through the point (1, 2) and parallel to the line y = 3x + 1 is
(a) y + 2 = x + 1
(b) y + 2 = 3 × (x + 1)
(c) y – 2 = 3 × (x – 1)
(d) y – 2 = x – 1
Answer: c
Solution Hint:
Given straight line is: y = 3x + 1Slope = 3
Now, required line is parallel to this line.
So, slope = 3
Hence, the line is
y – 2 = 3 × (x – 1)
Find slope of line if inclination made by the line is 60°.
a) 1/ 2
b) 1/√3
c) √3
d) 1
Answer: c
Question 9
Let the equation of the line be x/a + y/b = 1 which cuts off intercepts a and b with
the coordinate axes.
It is given that a = b, therefore the equation of the line is
x/a + y/a = 1 ⇒ x + y = a …..1
But it is passes through (α, β)
So, α + β = a
Put this value in equation 1, we get
x + y = α + β
Question 8
What is the inclination of a line which is parallel to
x-axis?
a) 0°
b) 180°
c) 45°
d) 90°
Answer: aQuestion 9
What is the inclination of a line which is parallel to
y-axis?
a) 0°
b) 180°
c) 45°
d) 90°
Answer: dQuestion 10
The equation of the line which cuts off equal and positive
intercepts from the axes and passes through the point (α, β) is
(a) x + y =
α + β
(b) x + y = α
(c) x + y = β
(d) None of these
Answer: a
Let the equation of the line be x/a + y/b = 1 which cuts off intercepts a and b with
the coordinate axes.
It is given that a = b, therefore the equation of the line is
x/a + y/a = 1 ⇒ x + y = a …..1
But it is passes through (α, β)
So, α + β = a
Put this value in equation 1, we get
x + y = α + β
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