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### Maths MCQ Class 11 Ch-10 | Straight Lines

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## __Mathematics__

MCQ | Class 11 | Chapter 10

__STRAIGHT LINES__

__Mathematics__

__Multiple Choice Questions (MCQ)__

__Multiple Choice Questions (MCQ)__

- MCQ Based on the Angle of inclination.
- MCQ Based on the Slopes of the straight lines
- MCQ Based on the Different Types of Straight Lines.

__Features__

__Features__

- In this pdf given below you find the important MCQ which are strictly according to the CBSE syllabus and are very useful for the CBSE Examinations.
- Solution Hints are also given to some difficult problems.
- Each MCQ contains four options from which one option is correct.
- On the right hand side column of the pdf Answer option is given.

__Action Plan__

__Action Plan__

- First of all students should Learn and write all basic points and Formulas related to the Continuity and Differentiability.
- Start solving the NCERT Problems with examples.
- Solve the important assignments on the Straight Lines Chapter 10 Class XI.
- Then start solving the following MCQ.

# MCQ | CHAPTER 10 | CLASS 11

STRAIGHT LINES

Question 1What is the distance between (1, 3) and (5, 6)?

a) 3 units

b) 4 units

c) 5 units

d) 25 units

Answer: c

Question 2

What is the distance of (5, 12) from origin?a) 6 units

b) 8 units

c) 10 units

d) 13 units

Answer: d

Question 3

The locus of a point, whose abscissa and ordinate are always equal is

(a) x + y + 1 = 0

(b) x – y = 0

(c) x + y = 1

(d) none of these.

Answer: b

(a) x + y + 1 = 0

(b) x – y = 0

(c) x + y = 1

(d) none of these.

Answer: b

Solution Hint: Let the
coordinate of the variable point P is (x, y)

Now, the abscissa of this point = x

and its ordinate = y

Given, abscissa = ordinate

⇒ x = y

⇒ x – y = 0

So, the locus of the point is x – y = 0

Now, the abscissa of this point = x

and its ordinate = y

Given, abscissa = ordinate

⇒ x = y

⇒ x – y = 0

So, the locus of the point is x – y = 0

Question 4

Angle made by line with ____________ measured anticlockwise is called inclination of the line.

a) positive x-axis

b) negative x-axis

c) positive y-axis

d) negative y-axis

Answer: a

Question 5

Slope of a line is given by _________ if inclination of line is α.

a) sinα

b) cosα

c) tanα

d) cotα

Answer: c

Question 6

The equation of straight line passing through the point (1, 2) and parallel to the line y = 3x + 1 is

(a) y + 2 = x + 1

(b) y + 2 = 3 × (x + 1)

(c) y – 2 = 3 × (x – 1)

(d) y – 2 = x – 1

Answer: c

Solution Hint:

Given straight line is: y = 3x + 1Slope = 3

Now, required line is parallel to this line.

So, slope = 3

Hence, the line is

y – 2 = 3 × (x – 1)

Find slope of line if inclination made by the line is 60°.

a) 1/ 2

b) 1/√3

c) √3

d) 1

Answer: c

Question 9

Let the equation of the line be x/a + y/b = 1 which cuts off intercepts a and b with

the coordinate axes.

It is given that a = b, therefore the equation of the line is

x/a + y/a = 1 ⇒ x + y = a …..1

But it is passes through (α, β)

So, α + β = a

Put this value in equation 1, we get

x + y = α + β

Question 8

What is the inclination of a line which is parallel to
x-axis?

a) 0°

b) 180°

c) 45°

d) 90°

Answer: aQuestion 9

What is the inclination of a line which is parallel to
y-axis?

a) 0°

b) 180°

c) 45°

d) 90°

Answer: dQuestion 10

The equation of the line which cuts off equal and positive
intercepts from the axes and passes through the point (α, β) is

(a) x + y =
α + β

(b) x + y = α

(c) x + y = β

(d) None of these

Answer: a

Let the equation of the line be x/a + y/b = 1 which cuts off intercepts a and b with

the coordinate axes.

It is given that a = b, therefore the equation of the line is

x/a + y/a = 1 ⇒ x + y = a …..1

But it is passes through (α, β)

So, α + β = a

Put this value in equation 1, we get

x + y = α + β

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