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FEATURED POST ON MATHS MCQ
Maths MCQ Ch-8 Class 10 | Trigonometry
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MATHEMATICS MCQ | Class 10 | Chapter 8
TRIGONOMETRY
c) Acute angled triangles d) Obtuse angled triangles
Q 2) The value of
a) tan θ b) cot θ c) cosec θ d) sec θ
Q 3) Trigonometric ratios are
a) sine, cosine and cotangent
b) sine, tangent, cotangent and secant
c) sine, cosine, tangent, cotangent, secant and cosecant
d) tangent, cotangent and secant
Q 4) Choose the correct reciprocal ratios.
a) Tan θ, Sec θ b) Cosec θ, Sec θ
c) Sec θ, Sin θ d) Tan θ, Cot θ
Q 5) What is the value of sec θ when θ is 45°?
a) √3 b) 1 c) 0 d) √2
Q 6) What is the value of sin 0° + cos 0° ?
a) 0 b) 2 c) 1 d) ∞
Q 7) Evaluate cos 30° sin 60° + cos 60° sin 30°.
a) 2 b) 0 c) 1 d) ∞
Q 8) The value of Cosec 0° is
a) Not defined b) 1 c) 0 d) 2
a) 2 b) 1 c) 4 d) 3
Q 10) The value of Cosec 90° is
a) 0 b) 2 c) 1 d) √3
(a) 45° (b) 30° (c) 29° (d) 52°
a) 2 b) 0 c) 1/ 4 d) ∞
(a) 12/ 7 (b) 24/ 7 (c) 20/ 7 (d) 7/ 24
Ans: b
Q 15) The product of sec 30° and cos 60° is
a) 0 b) 2 c) 1
a) ∠A + ∠B = 90° b) ∠A + ∠B = 180°
c) ∠A + ∠B = 60° d) ∠A + ∠B = 45°
a) Cot 25° + Tan 15° b) Cot 25° – Tan 15°
c) Cot 15° + Tan 25° d) Cot 15° – Tan 25°
a) Cosec 25° + Sec 15° b) Cosec 25° – Sec 15°
c) Cosec 15° + Sec 25° d) Cosec 15° – Sec 25°
(a) 0 (b) 1/2 (c) 2 (d) 1
a) tan2θ = sec2θ – 1 b) tan2θ + sec2θ = 1
c) tan2θ – sec2θ = 1 d) tan2θ = sec2θ + 1
a) 0 b) 1 c) 2 d) 3
Q 22) Evaluate cosec θ sec θ.
a) cos θ + tan θ b) cos θ – tan θ
c) tan θ – cot θ d) cot θ + tan θ
Q 23) (Sin 30° + cos 60°) - (sin 60° + cos 30°) is equal to:
(a) 0
(b) 1 + 2√3
(c) 1-√3
(d) 1+√3
Q 25) Evaluate sec2 A + (1 + tan A) (1 – tan A).
b) 0
c) 2
d) 1
a) Cot θ
b) 0
c) 1
d) Tan θ
Q 27) The value of
(a) 0
(b) 1
(c) 2
(d) 3
Q 28) The value of (Cos θ + sin θ)2 + (Cos θ - sin θ)2 is
a) -2
b) 0
c) 1
d) 2
(a) sin2A
(a) sin A
(b) tan A
(c) cos A
(d) cosec A
(a) Different
(b) Same
(c) Not related
(d) None of the above
Q 32) Find the value of
(a) sin60°
(b) cos60°
(c) tan60°
(d) sin30°
(a) 0
(b) 1
(c) 2
(d) 4
Q 34) Evaluate
(a) 0
(b) 1
(c) 1 / 2
(d) 2
Q 35) sin 2A = 2 sin A is true when A =
(a) 30°
(b) 45°
(c) 0°
(d) 60°
Q 36) The value of (sin 45° + cos 45°) is
(a) 1/√2
(b) 1
(c) √3/2
(d) √2
(a) √3
(b) 1/√3
(c) √3/2
(d) 1
Q 39) If ∆ABC is right angled at C, then the value of cos(A + B) is
(a) 1/2
(b) 1
(c) 0
(d) √3/2
Q 40) If x tan 45° sin 30° = cos 30° tan 30°, then x is equal to
(a) √3
(b) √3/2
(c) 1/2
(d) 1
Q 41)
Q 42) The value of (tan 1° tan 2° tan 3° … tan 89°) is
(a) 0
(b) 1
(c) 2
(d) ½
Ans: b
Explanation:
tan 1° tan 2° tan 3°…tan 89°
= [tan 1° tan 2°…tan 44°] tan 45° [tan (90° – 44°) tan (90° – 43°)…tan (90° – 1°)]
= [tan 1° tan 2°…tan 44°] [cot 44° cot 43°…cot 1°] × [tan 45°]
= [(tan 1°× cot 1°) (tan 2°× cot 2°)…(tan 44°× cot 44°)] × [tan 45°]
= 1 × 1 × 1 × 1 × …× 1 {since tan A × cot A = 1 and tan 45° = 1} = 1
Q 44) If sin A = 8/ 17 what will be the value of cos A sec A ?
a) 2
b) -1
c) 1
d) 0
a) -30°
b) 30°
c) 90°
d) 60°
a) 2
b) 0
c) 1
d) ∞
a) 0
b) 2
c) 1
d) 3
a) sin
2A = 2sinA
b) tan
A =
c)
sin(A + B) = sin A + sin B
d) (sin
A)2 = sin2 A
a)
b)
c)
d)
Ans: a
a) tan 60o
b) cos 30o
c) tan 30o
d) sin 30o
a) 24o, 18o
b) 18o, 24o
c) 24o, 28o
d) 20o, 24o
a) 24o, 18o
b) 18o, 26o
c) 28o, 24o
d) 24o, 30o
a) 0o
b) 30o
c) 60o
d) 90o
a) 210
b)
2
c) 25
d) 1
Ans: b
Solution
Hint
tanθ + 1/ tanθ = 2 ⇒ tan2 θ - 2tan θ + 1 = 0
Factorise this equation and then solving it we get θ = 45o
Using this value of θ and find the required valuea) 215
b)
1
c)
2
d) 0
Ans: c
Solution
Hint
sinθ + cosecθ = 2 = 1 + 1
sinθ = 1 and cosecθ = 1
sin15 θ + cosec 15 θ = (sinθ) 15 + (cosec θ) 15 = (1)15 + (1)15 = 1 + 1 = 2a) 45o
b) 30o
c) 60o
d) 90o
Ans: a
Solution
Hint
Dividing both side by cos2 θ we get
Sec2 θ + tan2 θ = 3 tan θ
1 + tan2 θ + tan2 θ = 3 tan θ
2 tan2 θ - 3 tanθ + 1 = 0
Factorise this equation we get tan θ = 1 or 1/2
tanθ = 1 ⇒ θ = 45oa) 1
b) - 1
c) 2
d) 3
Ans: a
Solution
Hint:
a) 3
b) 3/ 2
c) 2/
3
d) 0
Ans: d
Solution
Hint
sin θ +
cos θ = 1
Squaring
on both side and find the value of sin θ
cos θ
Questions From CBSE Sample Paper 2021-22
Basic Mathematics SP (241)
Q 62) If sinθ = x and secθ = y , then tanθ is(a)
xy
(b)
x/y
(c)
y/x
(d)
1/xy
Q 63) What is the value of (tanθ cosecθ)2 - (sinθ secθ)2
(a)
-1
(b)
0
(c)
1
(d)
2
Q 64) Given that sinθ = a/b ,then tanθ is equal to
Q 65) If x = 2sin2θand y = 2cos2θ+ 1 then x + y is
(a)
3
(b)
2
(c)
1
(d)
1/2
(a)
-1
(b)
0
(c)
1
(d)
2
(a)
3/4
(b)
5/12
(c)
4/3
(d)
12/5
Standard Mathematics SP(041)
(a)
-1
(b)
0
(c)
1
(d)
√3/2
Ans:
b
Solution Hint
tan A = √3 = tan 60° so ∠A = 60°, Hence ∠C = 30°.
(a)
0
(b)
1/2
(c)
1
(d)
√3/2
Ans:
a
Solution Hint
1x + 1x + 2x = 180°, x = 45°.
∠A , ∠B and ∠C are 45°, 45° and
90°resp.
(a)
0
(b)
1/3
(c)
2/3
(d)
3 ⁄ 4
(a)
0
(b)
2
(c)
20
(d)
220
Ans:
b
Solution Hint
tan α + cot α = 2 gives α = 45°. So tan α = cot α = 1
(a)
-1, 1
(b)
0, 1
(c)1,
2
(d)
-1, -1
Ans:
c
Solution Hint
1+ sin2α = 3 sinα cos α
sin2α + cos2α + sin2α = 3 sinα
cos α
2 sin2α - 3sinα cos α + cos2α = 0
(2sinα - cos α)( sinα - cosα) =0
(a) 0o (b) 90o (c) 45o (d) 30o
Ans: b(a) 2 (b) 1/2 (c) 1/3 (d) 1/4
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