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Maths MCQ Ch-11 Class 10 | Area Related to Circle
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MATHEMATICS
MCQ | CHAPTER 11 | CLASS 10
Area Related to the Circles
Q 1) What is the formula for the circumference of a circle?a) C = 2πd
b) C = 2πr
c) C = 2πa
d) C = 2πs
Q 2) What is the formula for the area of a circle?
a) A = πd2
b) A = πs2
c) A = πr2
d) A = πa2
Q 3) The circumference of the circle having diameter 8.4 cm is
a) 25.2 cm
b) 26.4 cm
c) 28 cm
d) 27.6
Q 4) The perimeter of a circle having radius 5cm is equal to:
(a) 30 cm
(b) 3.14 cm
(c) 31.4 cm
(d) 40 cm
Q 5) What is the circumference of a circle if the radius is 7 m?
a) 8 m
b) 2 m
c) 44 m
d) 22 m
Q 6) Area of the circle with radius 5cm is equal to:
(a) 60 sq.cm
(b) 75.5 sq.cm
(c) 78.5 sq.cm
(d) 10.5 sq.cm
Q 7) Find the area of the circle whose circumference is 44 cm.
a) 154 cm2
b) 308 cm2
c) 77 cm2
d) 231 cm2
a) 1.35 m
b) 6.54 m
c) 18.00 m
d) 8.05 m
Q 9) Find the radius of the circle if the circumference is 12 m.
a) 1.90 m
b) 1.09 m
c) 7.90 m
d) 1.40 m
Ans: a
(a) r2
(b) 1/2r2
(c) 2r2
(d) √2r2
Ans: a
a) √0.83 m
b) 5 m
c) √0.63 m
d) √38 m
Q 12) If the perimeter of the circle and square are equal, then the ratio of their areas will be equal to:
(a) 14:11
(b) 22:7
(c) 7:22
(d) 11:14
Q 13) The radius of a circle whose circumference is equal to the sum of the circumferences of the two circles of diameter 36 cm and 20 cm is
a) 28 cm
b) 42 cm
c) 56 cm
d) 16 cm
Q 14) The area of the circle that can be inscribed in a square of side 8 cm is
(a) 36 π cm2
(b) 16 π cm2
(c) 12 π cm2
(d) 9 π cm2
Ans: b
Solution Hint
Given, Side of square = 8 cm
Diameter of a circle = side of square = 8 cm
Therefore, Radius of circle = 4 cm Area of circle = π(4)2 = 16π cm2
(a) 256 cm2
(b) 128 cm2
(c) 642 cm2
(d) 64 cm2
Ans: b
Solution Hint
Radius of circle = 8 cm
Diameter of circle = 16 cm = diagonal of the square
Let “a” be the triangle side, and the hypotenuse is 16 cm
Using Pythagoras theorem, we can write
162 = a2 + a2 ⇒ 256 = 2a2 ⇒ a2 = 256/2 ⇒ a2 = 128 = Area of a Square
(a) 142/7
(b) 152/7
(c) 132/7
(d) 122/7
Ans: c
Solution Hint
Angle of the sector is 60°
Area of sector = (θ/360°) × π r2
∴ Area of the sector with angle 60° = (60°/360°) × π r2 cm2= (36/6) π cm2 = 6 × (22/7) cm2 = 132/7 cm2
a) Large
b) Major
c) Big
d) Wide
Q 18) What is the name of the sector with a smaller area?
a) Small
b) Narrow
c) Minor
d) Tiny
Q 19) Number of sectors in a circle are ____
a) 2
b) 3
c) 4
d) 1
Ans: a
Solution Hint
Q 20) In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. The length of the arc is;
(a) 20cm
(b) 21cm
(c) 22cm
(d) 25cm
a) 0.07 m
b) 0.47 cm
c) 0.79 m
d) 0.57 cm
Q 22) In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. The area of the sector formed by the arc is:
(a) 200 cm2
(b) 220 cm2
(c) 231 cm2
(d) 250 cm2
Ans: c
(a) p/180 × 2πR
(b) p/180 × π R2
(c) p/360 × 2πR
(d) p/720 × 2πR2
Ans: d
Q 24) If the area of a circle is 154 cm2, then its perimeter is
(b) 22 cm
(c) 44 cm
(d) 55 cm
Ans: c
Solution Hint
Given, Area of a circle = 154 cm2
πr2 = 154 ⇒ (22/7) × r2 = 154
(a) (πr2θ)/360
(d) (2πrθ)/180
Q 26) It is proposed to build a single circular park equal in area to the sum of areas of two circular parks of diameters 16 m and 12 m in a locality. The radius of the new park would be
(a) 10 m
(b) 15 m
(c) 20 m
(d) 24 m
Ans: a
(a) 56 cm
(b) 42 cm
(c) 28 cm
(d) 16 cm
Q 28) Find the area of a sector of circle of radius 21 cm and central angle 120°.
(a) 441 cm2
(b) 462 cm2
(c) 386 cm2
(d) 512 cm2
Ans: b
Q 29) The wheel of a motorcycle is of radius 35 cm. The number of revolutions per minute must the wheel make so as to keep a speed of 66 km/hr will be
(a) 50
(b) 100
(c) 500
(d) 1000
Ans: c
Solution Hint
Circumference of the wheel = 2πr = 2 × (22/7) × 35 = 220 cm
Speed of the wheel = 66 km/hr = (66 × 1000)/60 m/min
= 1100 × 100 cm/min = 110000 cm/min
Q 30) If the perimeter and the area of a circle are numerically equal, then the radius of the circle is
(a) 2 units
(b) π units
(c) 4 units
(d) 7 units
Q 31) The area of a quadrant of a circle with circumference of 22 cm is
(a) 77 cm2
(b) 77/8 cm2
(b) 35.5 cm2
(c) 77/2 cm2
Q 32) A chord of a circle of radius 10 cm subtends a right at the centre. Find length of the arc.
a) 16.7 cm
b) 15.7 cm
c) 15.2 cm
d) 14.7 cm
(a) 44 cm
(b) 28 cm
(c) 11 cm
(d) 22/3 cm
a) 14 cm
b) 7 cm
c) 21 cm
d) 10.5 cm
Ans: a
Solution Hint Find the radius by using the relation :
Q 35) The difference between circumference and diameter of a ring is 10 cm. Find the radius of the ring.
a) 3.07 cm
b) 0.37 cm
c) 2.33 cm
d) 4.57 cm
Ans: c
Solution Hint Circumference – Diameter = 10 cm (∵ Diameter = 2 × radius)
2πr – 2r = 10 cm ⇒ 2r(π – 1) = 10 cm
Q 36) The difference between the circumference and radius of a circle is 37 cm then area of the circle is
a) 111 cm2
b) 184 cm2
c) 154 cm2
d) 259 cm2
a) 3.07 m
b) 2.74 m
c) 2.33 m
d) 4.57 m
a) 54 m
b) 27m
c) 42 m
d) 56 m
Ans: a
Solution Hint
Q 39) Ratio of areas of two circles is 9 : 16. Find the ratio of their circumferences.
a) 9 : 16
b) 3 : 4
c) 16 : 9
d) 4 : 3
Q 40) If radius of a circle is increased by 20 % then its area will be increased by
a) 40 %
b) 42 %
c) 44 %
d) 45 %
Ans: c
Solution Hint
Find area by taking radius r
Find new area by taking radius = r + 20% of r
a)
20 %
b)
18 %
c)
19 %
d)
11 %
Ans:
c
Solution Hint
Take diameter = 2r and radius = r
Find area by taking radius r
Find new area by taking radius = (2r + 20% of 2r)
Find the difference of two areas
Ans: b
a) 42 cm2
b)
48 cm2
c)
38.5 cm2
d)
77 cm2
a) 54 cm2
b)
42 cm2
c)
48 cm2
d)
36 cm2
a)
16.3 cm2
b)
17.3 cm2
c)
18.8 cm2
d)
18.3 cm2
b)
231 cm2
c)
308 cm2
d)
316 cm2
a) 54 cm2
b) 42 cm2
c)
56 cm2
d)
48 cm2
b)
1416 cm2
c)
1308 cm2
d)
1386 cm2
b)
154 cm2
c)
308 cm2
d)
77 cm2
a) 36 cm2
b) 18 cm2
c) 12 cm2
d) 9 cm2
Ans: da)
256 cm2
b)
128 cm2
c)
64 cm2
d)
77 cm2
Questions
from CBSE Sample paper 2021-22
Basic
Mathematics (241)
Q 52) In a circle of diameter 42cm ,if an arc subtends an angle of 60 ̊ at the centre where 𝜋 = 22/7,then the length of the arc is
(a) 22/7 cm
(b) 11cm
(c) 22 cm
(d) 44 cm
Ans: c
Q 53) If the circumference of a circle increases from 2𝜋 to 4𝜋 then its area _____ the original area
(a) Half
(b) Double
(c) Three times
(d) Four times
Ans: d
(a) 154
(b) 44
(c) 14
(d) 7
Ans: b
Q 55) The perimeter of a semicircular protractor whose radius is ‘r’ is
(a) 𝜋 + 2r
(b) 𝜋 + r
(c) 𝜋 r
(d) 𝜋 r + 2r
Ans: d
Perimeter of protractor = Circumference of semi-circle + 2 x radius = 𝜋 r + 2r
Q 56) Area of a sector of a circle is 1/6 to the area of circle. Find the degree measure of its minor arc.
(a)
90 ̊
(b)
60 ̊
(c)
45 ̊
(d)
30 ̊
Standard Maths SPQ (041)
Q 57) The number of revolutions made by a circular wheel of radius 0.7m in rolling a distance of 176m is(a)
22
(b)
24
(c)
75
(d)
40
Q 58) In the figure given below, ABCD is a square of side 14 cm with E, F, G and H as the mid points of sides AB, BC, CD and DA respectively. The area of the shaded portion is
(b)
49 cm2
(c)
98 cm2
(d)
49π/2 cm2
Ans:
c
Solution Hint
Shaded area = Area of semicircle + (Area of half square – Area
of two quadrants)
=
Area of semicircle + (Area of half square – Area of semicircle)
(b)
(π/6 - √3/4) cm2
(c)
4(π/6 - √3/4) cm2
(d)
8(π/6 - √3/4) cm2
Ans: d
Solution Hint
Let O be the center of
the circle. OA = OB = AB = 1cm.
So ∆OAB is an equilateral triangle and ∴ ∠AOB = 60°
(a)
50√2 cm
(b)
100/π cm
(c)
50√2/π cm
(d)
100√2/π cm
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